TY - GEN
T1 - Upper and lower degree bounded graph orientation with minimum penalty
AU - Asahiro, Yuichi
AU - Jansson, Jesper
AU - Miyano, Eiji
AU - Ono, Hirotaka
PY - 2012/7/24
Y1 - 2012/7/24
N2 - Given an undirected graph G = (V,E), a graph orientation problem is to decide a direction for each edge so that the resulting directed graph G = (V, Λ(E)) satisfies a certain condition, where Λ(E) is a set of assignments of a direction to each edge {u, v} ∈ E. Among many conceivable types of conditions, we consider a degree constrained orientation: Given positive integers a v and b v for each v (a v ≤ b v), decide an orientation of G so that a v ≤ {pipe}{(v, u) ∈ Λ(E)}{pipe} ≤ b v holds for every v ∈ V. However, such an orientation does not always exist. In this case, it is desirable to find an orientation that best fits the condition instead. In this paper, we consider the problem of finding an orientation that minimizes Σ v∈V cv, where c v is a penalty incurred for v's violating the degree constraint. As penalty functions, several classes of functions can be considered, e.g., linear functions, convex functions and concave functions. We show that the degree-constrained orientation with any convex (including linear) penalty function can be solved in O(m 1:5 min{Δ 0:5, log(nC)}), where n = {pipe}V{pipe},m = {pipe}E{pipe}, Δ and C are the maximum degree and the largest magnitude of a penalty, respectively. In contrast, it has no polynomial approximation algorithm whose approximation factor is better than 1.3606, for concave penalty functions, unless P=NP; it is APX-hard. This holds even for step functions, which are considered concave. For trees, the problem with any penalty functions can be solved exactly in O(n log Δ) time, and if the penalty function is convex, it is solvable in linear time.
AB - Given an undirected graph G = (V,E), a graph orientation problem is to decide a direction for each edge so that the resulting directed graph G = (V, Λ(E)) satisfies a certain condition, where Λ(E) is a set of assignments of a direction to each edge {u, v} ∈ E. Among many conceivable types of conditions, we consider a degree constrained orientation: Given positive integers a v and b v for each v (a v ≤ b v), decide an orientation of G so that a v ≤ {pipe}{(v, u) ∈ Λ(E)}{pipe} ≤ b v holds for every v ∈ V. However, such an orientation does not always exist. In this case, it is desirable to find an orientation that best fits the condition instead. In this paper, we consider the problem of finding an orientation that minimizes Σ v∈V cv, where c v is a penalty incurred for v's violating the degree constraint. As penalty functions, several classes of functions can be considered, e.g., linear functions, convex functions and concave functions. We show that the degree-constrained orientation with any convex (including linear) penalty function can be solved in O(m 1:5 min{Δ 0:5, log(nC)}), where n = {pipe}V{pipe},m = {pipe}E{pipe}, Δ and C are the maximum degree and the largest magnitude of a penalty, respectively. In contrast, it has no polynomial approximation algorithm whose approximation factor is better than 1.3606, for concave penalty functions, unless P=NP; it is APX-hard. This holds even for step functions, which are considered concave. For trees, the problem with any penalty functions can be solved exactly in O(n log Δ) time, and if the penalty function is convex, it is solvable in linear time.
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M3 - Conference contribution
AN - SCOPUS:84864023399
SN - 9781921770098
T3 - Conferences in Research and Practice in Information Technology Series
SP - 139
EP - 146
BT - Theory of Computing 2012 - Proceedings of the Eighteenth Computing
T2 - Theory of Computing 2012 - 18th Computing: The Australasian Theory Symposium, CATS 2012
Y2 - 31 January 2012 through 3 February 2012
ER -