The mechanism of the decomposition reaction of 2-propanol on ZnO at 363 was studied by a volumetric method following the change in the composition of surface species as well as that of the gas phase. The order of the hydrogen formation reaction as to surface coverage of 2-propanol was 1.7 in the initial stage and 0.8 in the steady state of the reaction. By using deuterated 2-propanol as a reactant, it was confirmed that a hydrogen molecule is formed by the recombination of hydrogen attached to the α-carbon of a surface alcohólate with hydrogen of a surface hydroxyl group which is formed by dissociative adsorption of 2-propanol. The rate-determining step of the overall reaction is concluded to be the dehydrogenation of a surface alcohólate to form an enol type adsórbate and a hydrogen molecule on the catalyst surface.
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